Class 9

Class 9 Mathematics Complete Guide - Algebra, Geometry, Arithmetic

Complete Class 9 Mathematics guide covering all chapters: algebra, geometry, arithmetic, statistics with formulas, examples, and practice problems for CDC curriculum.

Subesh Yadav··Updated May 28, 2026·13 min read

Introduction to Class 9 Mathematics#

Class 9 Mathematics builds the foundation for SEE-level mathematics. The CDC curriculum covers Algebra, Geometry, Arithmetic, and Statistics. Strong basics here make Class 10 much easier.

Algebra#

Unit 1: Sets#

Definition
Set

A well-defined collection of distinct objects.

NotationMeaningExample
A = {1, 2, 3}Roster form-
B = {x : x is even, x < 10}Set-builderB = {2, 4, 6, 8}
A ⊂ BA is subset of B{1,2} ⊂ {1,2,3}
A ∪ BUnion{1,2} ∪ {2,3} = {1,2,3}
A ∩ BIntersection{1,2} ∩ {2,3} = {2}
A'ComplementU = {1..5}, A={1,2} → A'={3,4,5}
n(A)Cardinal numbern({a,b,c}) = 3

Important Formulas

  • n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
  • n(A ∪ B ∪ C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) - n(C∩A) + n(A∩B∩C)
  • De Morgan's Laws: (A ∪ B)' = A' ∩ B', (A ∩ B)' = A' ∪ B'

Unit 2: Polynomials#

Algebraic Expressions

TypeFormDegree
Monomial3x², 52, 0
Binomialx² + 2x, 3x - 5max of terms
Trinomialx² + 2x + 1max of terms
Polynomialaₙxⁿ + ... + a₁x + a₀n

Operations

Polynomial Operations

Addition: (2x² + 3x + 1) + (x² - 2x + 4) = 3x² + x + 5 Subtraction: (3x² + 2x - 1) - (x² - x + 2) = 2x² + 3x - 3 Multiplication: (x + 2)(x - 3) = x² - x - 6 Division: (x² + 5x + 6) ÷ (x + 2) = x + 3 (remainder 0)

Factorization

MethodFormExample
Common factorax + ay = a(x + y)3x² + 6x = 3x(x + 2)
Groupingax + ay + bx + by = (a+b)(x+y)x² + 5x + 6 = (x+2)(x+3)
Difference of squaresa² - b² = (a+b)(a-b)x² - 9 = (x+3)(x-3)
Perfect squarea² ± 2ab + b² = (a ± b)²x² + 6x + 9 = (x+3)²
Quadratic trinomialx² + (p+q)x + pq = (x+p)(x+q)x² + 7x + 12 = (x+3)(x+4)

Remainder and Factor Theorems

Important Theorems
  • Remainder Theorem: If f(x) is divided by (x - a), remainder = f(a)
  • Factor Theorem: (x - a) is factor of f(x) iff f(a) = 0
Finding Factors

f(x) = x³ - 6x² + 11x - 6 f(1) = 1 - 6 + 11 - 6 = 0 → (x-1) is factor Divide: (x-1)(x² - 5x + 6) = (x-1)(x-2)(x-3)

Unit 3: Sequences and Series#

Arithmetic Progression (AP)

FormulaExpression
nth termaₙ = a + (n-1)d
Sum of n termsSₙ = n/2 [2a + (n-1)d] = n/2 (a + l)
Arithmetic MeanA = (a + b)/2
AP Problems

Find 10th term of AP: 3, 7, 11, ... a = 3, d = 4 a₁₀ = 3 + 9×4 = 39

Sum of first 20 terms of 2, 5, 8, ... S₂₀ = 20/2 [2×2 + 19×3] = 10 × 61 = 610

Geometric Progression (GP)

FormulaExpression
nth termaₙ = arⁿ⁻¹
Sum of n termsSₙ = a(rⁿ - 1)/(r - 1) for r ≠ 1
Sum to infinityS∞ = a/(1-r) for
Geometric MeanG = √(ab)
GP Problems

3, 6, 12, 24, ... Find 8th term. a = 3, r = 2 a₈ = 3 × 2⁷ = 384

Sum of infinite GP: 1 + 1/2 + 1/4 + 1/8 + ... a = 1, r = 1/2 S∞ = 1/(1 - 1/2) = 2

Unit 4: Quadratic Equations#

MethodWhen to Use
FactorizationWhen factors are integers
Quadratic FormulaAlways works
Completing SquareFor deriving formula
GraphicalFor approximate roots
Definition
Quadratic Formula

For ax² + bx + c = 0 (a ≠ 0): x = [-b ± √(b² - 4ac)] / 2a Discriminant: D = b² - 4ac

  • D > 0: Real distinct roots
  • D = 0: Real equal roots
  • D < 0: Imaginary roots
Quadratic Problems

Solve: 2x² - 5x + 2 = 0 D = 25 - 16 = 9 x = (5 ± 3)/4 → x = 2, x = 1/2

If roots of x² - 5x + k = 0 are equal, find k. D = 25 - 4k = 0 → k = 25/4

Unit 5: Inequalities#

PropertyRule
Additiona > b → a + c > b + c
Multiplication by positivea > b, c > 0 → ac > bc
Multiplication by negativea > b, c < 0 → ac < bc
Reciprocala > b > 0 → 1/a < 1/b
Squaringa > b > 0 → a² > b²
Inequality Problems

Solve: 3x - 7 > 2x + 5 x > 12

Solve: (x-2)/(x+3) > 0 Critical points: x = 2, x = -3 Intervals: (-∞, -3): +/(-) = - ✗ (-3, 2): +/(+) = + ✓ (2, ∞): +/(+) = + ✓ Solution: (-3, 2) ∪ (2, ∞)

Geometry#

Unit 6: Lines and Angles#

Angle PairProperty
AdjacentShare vertex and arm
Linear pairSum = 180°
Vertically oppositeEqual
CorrespondingEqual (if lines parallel)
Alternate interiorEqual (if lines parallel)
Alternate exteriorEqual (if lines parallel)
Interior on same sideSupplementary (if parallel)

Unit 7: Triangles#

Congruence Criteria

CriterionCondition
SSSThree sides equal
SASTwo sides and included angle
ASATwo angles and included side
AASTwo angles and non-included side
RHSRight angle, hypotenuse, side

Similarity Criteria

CriterionCondition
AATwo angles equal
SSSSides proportional
SASTwo sides proportional, included angle equal
Important Triangle Theorems

Unit 8: Quadrilaterals#

QuadrilateralProperties
ParallelogramOpposite sides parallel & equal, diagonals bisect
RectangleAll angles 90°, diagonals equal
RhombusAll sides equal, diagonals perpendicular bisect
SquareRectangle + Rhombus
TrapeziumOne pair of parallel sides
KiteTwo pairs of adjacent equal sides
Area Formulas

Unit 9: Circles#

TheoremStatement
1Perpendicular from center bisects chord
2Equal chords equidistant from center
3Angle at center = 2 × angle at circumference
4Angles in same segment are equal
5Angle in semicircle = 90°
6Opposite angles of cyclic quadrilateral = 180°
7Tangent ⟂ radius at point of contact
8Tangents from external point are equal
9Alternate segment theorem
Circle Problems

Chord length 12 cm, distance from center 5 cm. Find radius. r² = 5² + 6² = 61 → r = √61 cm

Cyclic quadrilateral ABCD, ∠A = 70°. Find ∠C. ∠C = 180° - 70° = 110°

Unit 10: Constructions#

ConstructionSteps Summary
Perpendicular bisectorArcs from endpoints, join intersections
Angle bisectorArc from vertex, arcs from intersections, join
Triangle (SSS)Draw base, arcs from endpoints with other sides
Triangle (SAS)Draw side, angle, other side
Triangle (ASA)Draw side, two angles
Circle through 3 pointsPerpendicular bisectors of chords intersect at center
Tangent at pointPerpendicular to radius
Tangents from externalCircle on diameter from external to center

Arithmetic#

Unit 11: Percentage, Profit and Loss#

FormulaExpression
ProfitSP - CP
LossCP - SP
Profit %(Profit/CP) × 100
Loss %(Loss/CP) × 100
SP with profitCP(1 + P%/100)
SP with lossCP(1 - L%/100)
CP from SP & profitSP × 100/(100 + P%)
DiscountMP - SP
Discount %(Discount/MP) × 100
Arithmetic Problems

Article marked 40% above CP, sold at 15% discount. Profit %? CP = 100, MP = 140 SP = 140 × 0.85 = 119 Profit = 19%

Two successive discounts of 20% and 10% = single discount? Effective = 1 - 0.8×0.9 = 0.28 = 28%

Unit 12: Simple and Compound Interest#

TypeFormula
Simple InterestSI = PRT/100
Amount (SI)A = P + SI = P(1 + RT/100)
Compound Interest (annual)A = P(1 + R/100)ᵀ
Compound Interest (half-yearly)A = P(1 + R/200)²ᵀ
Compound Interest (quarterly)A = P(1 + R/400)⁴ᵀ
CIA - P
Interest Problems

Find CI on 5000 at 10% for 2 years, compounded annually. A = 5000(1.1)² = 6050 CI = 1050

Difference between CI and SI on 10000 at 5% for 2 years? SI = 1000, CI = 1025, Difference = 25

Unit 13: Ratio, Proportion and Variation#

ConceptFormula/Rule
Ratioa
= a/b
Proportiona
= c
→ ad = bc
Continued proportiona
= b
→ b² = ac
Direct variationx ∝ y → x = ky
Inverse variationx ∝ 1/y → xy = k
Joint variationx ∝ yz → x = kyz

Statistics#

Unit 14: Measures of Central Tendency#

MeasureFormula
Mean (ungrouped)x̄ = Σx/n
Mean (grouped)x̄ = Σfx/Σf
Median (odd n)Middle value
Median (even n)Average of middle two
Median (grouped)L + (N/2 - cf)/f × h
Mode (grouped)L + (f₁-f₀)/(2f₁-f₀-f₂) × h

Unit 15: Measures of Dispersion#

MeasureFormula
RangeMax - Min
Mean DeviationΣf
Varianceσ² = Σf(x - x̄)²/Σf
Standard Deviationσ = √Variance
Coefficient of VariationCV = σ/x̄ × 100%
Statistics Problems

Data: 10, 15, 20, 25, 30 Mean = 100/5 = 20 Median = 20 Mode = No mode (all unique)

Variance = [(100+25+0+25+100)/5] = 50 SD = √50 ≈ 7.07 CV = 7.07/20 × 100 = 35.35%

Practice Problems#

Algebra:

  1. If A = {1,2,3,4}, B = {3,4,5,6}, find A∪B, A∩B, A-B, B-A
  2. Factorize: x⁴ - 16, x³ + 8, x² - 5x + 6
  3. Solve: x² - 7x + 10 = 0, 2x² - x - 6 = 0
  4. Find sum of first 15 terms of AP: 5, 8, 11, ...
  5. If a, b, c are in GP, prove a², b², c² are in GP

Geometry:

  1. Prove: In ΔABC, if AB = AC, then ∠B = ∠C
  2. In parallelogram ABCD, prove diagonals bisect each other
  3. If two circles intersect at A and B, prove line joining centers is perpendicular bisector of AB
  4. Construct triangle with sides 5cm, 6cm, 7cm
  5. Find radius of circle with chord 10cm at distance 12cm from center

Arithmetic:

  1. A man sells two articles for Rs 990 each. On one he gains 10%, on other loses 10%. Overall gain/loss?
  2. Find difference between CI and SI on Rs 5000 at 12% for 2 years
  3. If x
    = 2
    and y
    = 4
    , find x:y

Statistics:

  1. Find mean, median, mode of: 5, 8, 8, 10, 12, 12, 12, 15, 18
  2. Find SD of: 5, 10, 15, 20, 25
  3. If CV = 25% and mean = 40, find SD

Exam Preparation Tips#

WeekFocusActivities
1-2AlgebraSets, polynomials, factorization
3-4AlgebraQuadratics, sequences, inequalities
5-6GeometryTriangles, circles, constructions
7ArithmeticPercentage, interest, ratio
8StatisticsMean, median, mode, SD
9-10Full RevisionPast papers, mock tests

Conclusion#

Class 9 Mathematics is about building solid fundamentals. Don't just memorize formulas—understand the derivations. Practice 10-15 problems daily, focusing on weak areas. Regular geometry construction practice is essential. With consistent effort, you'll build a strong foundation for SEE.

The only way to learn mathematics is to do mathematics.

Good luck with your Class 9 Mathematics!

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