Class 11

Class 11 Chemistry Complete Notes - Physical and Inorganic Chemistry

Comprehensive Class 11 Chemistry notes covering Physical Chemistry (States of Matter, Atomic Structure) and Inorganic Chemistry (Periodic Properties, Chemical Bonding) for NEB.

Subesh Yadav··Updated May 25, 2026·14 min read
Table of Contents

Introduction to Class 11 Chemistry#

Class 11 Chemistry under NEB covers Physical Chemistry, Inorganic Chemistry, and Organic Chemistry basics. This guide focuses on Physical and the next post cover the complete syllabus.

Physical Chemistry#

Unit 1: States of Matter#

Gas Laws

LawEquationVariablesConstant
Boyle'sPV = constantP, VT, n
Charles'sV/T = constantV, TP, n
Gay-Lussac'sP/T = constantP, TV, n
Avogadro'sV/n = constantV, nP, T
Ideal GasPV = nRTP, V, n, TR = 0.0821 L·atm/mol·K

Dalton's Law of Partial Pressures

Ptotal = P1 + P2 + P3 + ... = ΣPi Pi = Xi × Ptotal (where Xi = mole fraction)

Graham's Law of Diffusion

Rate1/Rate2 = √(M2/M1) (inversely proportional to square root of molar mass)

Gas Law Problem

2 moles of gas at 300 K in 10 L. Find pressure. P = nRT/V = 2 × 0.0821 × 300 / 10 = 4.926 atm

Kinetic Molecular Theory

Postulates of KMT
  1. Gas particles are in constant random motion
  2. Volume of particles is negligible
  3. No intermolecular forces
  4. Collisions are perfectly elastic
  5. Average KE ∝ absolute temperature

Real Gases - Van der Waals Equation

(P + an²/V²)(V - nb) = nRT

  • a: accounts for intermolecular attraction
  • b: accounts for molecular volume

Unit 2: Atomic Structure#

Bohr's Model

PostulateDescription
1Electrons in fixed circular orbits
2Angular momentum quantized: mvr = nh/2π
3Energy change: ΔE = hν = Ef - Ei
4Ground state = lowest energy (n=1)

Energy of Electron in nth Orbit

En = -13.6/n² eV (for hydrogen) rn = 0.529 n² Å

Atomic Transition

Hydrogen electron from n=3 to n=2. Find wavelength.

ΔE = 13.6(1/4 - 1/9) = 13.6 × 5/36 = 1.89 eV λ = 1240/1.89 ≈ 656 nm (Balmer series, red line)

Quantum Numbers

Quantum NumberSymbolValuesSignificance
Principaln1, 2, 3...Shell, energy, size
Azimuthall0 to n-1Subshell (s,p,d,f), shape
Magneticml-l to +lOrbital orientation
Spinms+½, -½Electron spin

Electronic Configuration Rules

  1. Aufbau Principle: Fill lower energy first (1s, 2s, 2p, 3s, 3p, 4s, 3d...)
  2. Pauli Exclusion: No two electrons with same 4 quantum numbers
  3. Hund's Rule: Maximize unpaired electrons in degenerate orbitals
  4. (n+l) Rule: Lower (n+l) fills first; if equal, lower n fills first
Configuration Examples
  • Cr (24): [Ar] 4s¹ 3d⁵ (half-filled d is stable)
  • Cu (29): [Ar] 4s¹ 3d¹⁰ (filled d is stable)
  • Fe (26): [Ar] 4s² 3d⁶

Unit 3: Chemical Bonding#

Ionic Bond

Formed by complete electron transfer.

PropertyDescription
FormationMetal + Non-metal
Electronegativity difference> 1.7
ConductivityConducts in molten/aqueous state
Melting/BoilingHigh
SolubilitySoluble in polar solvents

Covalent Bond

TypeElectronegativity DiffExample
Non-polar covalent< 0.4H₂, Cl₂, O₂
Polar covalent0.4 - 1.7H₂O, NH₃, HCl
Coordinate (dative)Both electrons from one atomNH₄⁺, H₃O⁺

VSEPR Theory

Steric NumberShapeBond AngleExamples
2Linear180°CO₂, BeCl₂
3Trigonal planar120°BF₃, SO₃
3 (1 lone pair)Bent/V-shaped~119°SO₂, O₃
4Tetrahedral109.5°CH₄, CCl₄
4 (1 lone pair)Trigonal pyramidal~107°NH₃, PCl₃
4 (2 lone pairs)Bent/V-shaped~104.5°H₂O, OF₂
5Trigonal bipyramidal90°, 120°PCl₅
6Octahedral90°SF₆

Hybridization

Steric No.HybridizationGeometryExample
2spLinearBeCl₂, CO₂
3sp²Trigonal planarBF₃, C₂H₄
4sp³TetrahedralCH₄, NH₃, H₂O
5sp³dTrigonal bipyramidalPCl₅
6sp³d²OctahedralSF₆
Hybridization Examples

Molecular Orbital Theory

MOT Key Points
MoleculeConfigurationBond OrderMagnetic
H₂σ1s²1Diamagnetic
He₂σ1s² σ*1s²0Unstable
N₂σ2s² σ*2s² π2p⁴ σ2p²3Diamagnetic
O₂σ2s² σ2s² σ2p² π2p⁴ π2p²2Paramagnetic
F₂σ2s² σ2s² σ2p² π2p⁴ π2p⁴1Diamagnetic

Unit 4: Periodic Properties#

PropertyAcross PeriodDown GroupReason
Atomic RadiusDecreasesIncreasesEffective nuclear charge / shells
Ionization EnergyIncreasesDecreasesNuclear attraction / shielding
Electron AffinityIncreasesDecreasesNuclear attraction / distance
ElectronegativityIncreasesDecreasesNuclear attraction / distance
Metallic CharacterDecreasesIncreasesElectron loss tendency
Exam Tip

Exceptions: IE drops from Group 2→13 (Be→B), 15→16 (N→O) due to subshell stability. EA of Cl > F due to small size repulsion in F.

Inorganic Chemistry#

Unit 5: Hydrogen#

PropertyDetail
PositionGroup 1 and 17 (unique)
IsotopesProtium (¹H), Deuterium (²H), Tritium (³H)
PreparationZn + 2HCl → ZnCl₂ + H₂↑
UsesNH₃ synthesis, HCl, hydrogenation, fuel

Unit 6: Alkali Metals (Group 1)#

PropertyTrendNote
Reactivity with waterIncreases downLi < Na < K < Rb < Cs
Flame colorLi: Crimson, Na: Golden yellow, K: Lilac, Rb: Red-violet, Cs: Blue
OxidesLi₂O, Na₂O₂, KO₂, RbO₂, CsO₂Peroxide/Superoxide stability increases

Unit 7: Alkaline Earth Metals (Group 2)#

PropertyComparison with Group 1
HardnessHarder
Melting/Boiling pointsHigher
ReactivityLess reactive
Ionization energyHigher
Solubility of hydroxidesIncreases down (Be(OH)₂ insoluble)
Solubility of sulfatesDecreases down
Solubility of carbonatesDecreases down

Unit 8: Boron Family (Group 13)#

Unit 9: Carbon Family (Group 14)#

Unit 10: Nitrogen Family (Group 15)#

Unit 11: Oxygen Family (Group 16)#

Unit 12: Halogens (Group 17)#

PropertyF₂Cl₂Br₂I₂
StateGasGasLiquidSolid
ColorPale yellowGreenish yellowReddish brownViolet
Oxidizing powerStrongestStrongModerateWeak
ReactivityHighestHighModerateLow

Unit 13: Noble Gases (Group 18)#

Important Reactions for NEB#

Preparation of Gases:

  • H₂: Zn + 2HCl → ZnCl₂ + H₂↑
  • O₂: 2KClO₃ → 2KCl + 3O₂↑ (MnO₂ catalyst)
  • N₂: NH₄Cl + NaNO₂ → N₂ + 2H₂O + NaCl
  • CO₂: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂↑
  • NH₃: 2NH₄Cl + Ca(OH)₂ → 2NH₃ + CaCl₂ + 2H₂O
  • Cl₂: MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O
  • SO₂: Cu + 2H₂SO₄ → CuSO₄ + SO₂ + 2H₂O
  • H₂S: FeS + 2HCl → FeCl₂ + H₂S↑

Qualitative Analysis (Cations):

  • Group I: Pb²⁺, Ag⁺ (HCl → white ppt)
  • Group II: Cu²⁺, Cd²⁺, Bi³⁺, Hg²⁺ (H₂S in acidic)
  • Group III: Fe³⁺, Al³⁺, Cr³⁺ (NH₄OH + NH₄Cl → hydroxide ppt)
  • Group IV: Co²⁺, Ni²⁺, Mn²⁺, Zn²⁺ (H₂S in basic)
  • Group V: Ba²⁺, Sr²⁺, Ca²⁺ (NH₄)₂CO₃ → carbonate ppt

Practice Problems#

1. Gas Laws: 500 ml gas at 2 atm compressed to 1 atm. New volume? P₁V₁ = P₂V₂ → 2 × 500 = 1 × V₂ → V₂ = 1000 ml

2. Atomic Structure: Wavelength for n=4→2 in He⁺? (Z=2) 1/λ = RZ²(1/n₁² - 1/n₂²) = 109678 × 4 × (1/4 - 1/16) = 109678 × 4 × 3/16 = 82258 cm⁻¹ λ = 121.5 nm

3. Periodic Properties: IE of Mg > Al? Yes. Mg: [Ne]3s² (stable), Al: [Ne]3s²3p¹ (easier to remove p electron)

4. Bonding: Bond order of O₂⁺? O₂: (8-4)/2 = 2. O₂⁺: (8-3)/2 = 2.5

5. Chemical Equilibrium: For N₂ + 3H₂ ⇌ 2NH₃, Kc = [NH₃]²/[N₂][H₂]³ If [N₂]=1M, [H₂]=3M, [NH₃]=2M at eq: Kc = 4/(1×27) = 0.148

Conclusion#

Class 11 Chemistry requires balancing conceptual understanding with problem-solving skills. Physical Chemistry needs formula mastery and numerical practice. Inorganic Chemistry requires understanding trends and memorizing key reactions. Regular revision of periodic properties and bonding concepts is essential.

The best way to have a good idea is to have lots of ideas.

Good luck with your NEB Chemistry preparation!

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